3y^2(y-4)+7(y-4)=

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Solution for 3y^2(y-4)+7(y-4)= equation: 


Simplifying
3y2(y + -4) + 7(y + -4) = 0

Reorder the terms:
3y2(-4 + y) + 7(y + -4) = 0
(-4 * 3y2 + y * 3y2) + 7(y + -4) = 0
(-12y2 + 3y3) + 7(y + -4) = 0

Reorder the terms:
-12y2 + 3y3 + 7(-4 + y) = 0
-12y2 + 3y3 + (-4 * 7 + y * 7) = 0
-12y2 + 3y3 + (-28 + 7y) = 0

Reorder the terms:
-28 + 7y + -12y2 + 3y3 = 0

Solving
-28 + 7y + -12y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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